2x^2+4x+19=0

Solution for 2x^2+4x+19=0 equation:

Simplifying
2x2 + 4x + 19 = 0

Reorder the terms:
19 + 4x + 2x2 = 0

Solving
19 + 4x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
9.5 + 2x + x2 = 0

Move the constant term to the right:

Add '-9.5' to each side of the equation.
9.5 + 2x + -9.5 + x2 = 0 + -9.5

Reorder the terms:
9.5 + -9.5 + 2x + x2 = 0 + -9.5

Combine like terms: 9.5 + -9.5 = 0.0
0.0 + 2x + x2 = 0 + -9.5
2x + x2 = 0 + -9.5

Combine like terms: 0 + -9.5 = -9.5
2x + x2 = -9.5

The x term is 2x.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2x + 1 + x2 = -9.5 + 1

Reorder the terms:
1 + 2x + x2 = -9.5 + 1

Combine like terms: -9.5 + 1 = -8.5
1 + 2x + x2 = -8.5

Factor a perfect square on the left side:
(x + 1)(x + 1) = -8.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.